A race car driver starts a race with his tires at 13.2 psi at a temperature of 25 C. What will the pressure in the tires be (in psi) when they heat up to 63 C?

P₂ = 14.88 psi

Explanation:

Given data:

Initial pressure of tires = 13.2 psi

Initial temperature = 25°C (25+273 = 298 K)

Final pressure in tires = ?

Final temperature = 63°C (63+273 = 336 K)

Solution:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

13.2 / 298 K = P₂/336 K

P₂ = 13.2 psi × 336 K / 298 K

P₂ = 4435.2 psi. K /298 K

P₂ = 14.88 psi

definition

                    entropy is a measure of the randomness or the extent of disorder of a chemical process.

                      enthalpy is a measure of the heat change of a reaction occurring at a constant pressure.

measurement units:

                        entropy is measured in joule per kelvin (jk⁻¹)   whereas enthalpy is measured in joule per mole (jmol⁻¹)

requirements:

                            entropy has no requirements or limits, and its change is measured by the division between the heat change of the chemical process and the temperature.

                              in contrast, enthalpy can only be related to the heat change of the reaction under standard conditions.