How many grams of N205 gas are in sample that has a volume of 2.00 liters at 298 k and 100

883.44g

Explanation:

let us assume that the unit of the pressure is given in "atm" since it was not clearly stated in this problem.

Given parameters:

Volume of gas  = 2liters

Temperature of gas =  298K

Pressure on the gas = 100atm

Unknown :

Mass of the gas  = ?

Solution:

Applying the ideal gas law and the mathematical equation will give us a problem where we can easily solve for the number of moles.

After finding the number of moles, the mass is easy to deduce from it.

Ideal gas equation is given as:

                         PV  = nRT

where P is the pressure on the gas

          V is the volume of the gas

          n is the number of moles

         R is the gas constant  = 0.082atm dm³mol⁻¹K⁻¹

         T is the temperature on the gas

Now let us solve for the number of moles;

                 100 x 2   = n x 0.082 x 298

                    n  = 8.18moles

  Since;

                   mass  = number of moles x molar mass

Molar mass of N₂O₅  = 2(14) + 5(16)  = 108g/mol

                Mass of N₂O₅  = 8.18 x 108  = 883.44g

the right answer is c i just did the question.