If 3.03 mol of ethane (C2H6) undergoes combustion according to the unbalanced equation
C2H6+O2 > CO2+ H2O
how many moles of O is required?

10.06 mol O₂

Explanation:

2C₂H₆ + 7O₂ => 4CO₂ + 6H₂O

Given 3.03 moles C₂H₆ combustion reaction requires 7/2(3.03 mol) O₂

= 10.06 mol O₂

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here is table 2-2:

country

percent of eligible voters that voted

rank

united states

44.9%

138

canada

60.1%

107

costa rica

84.6%

14

hungary

66.9%

82

japan

57.0%

118

egypt

27.7%

159

south africa

85.5%

10

ans is no, the data set cannot be plotted as a single circle graph