Question 4: Balancing Redox Equations (9 points)
a. Use the following steps to balance the redox reaction below. (4 points)
Fe2+ + Cl2 Fe3+ + Cl–
i. Write the oxidation and reduction half-reactions. Make sure each half-reaction is balanced for the number of atoms and charge. (2 points)
ii. Equalize charges for the two half-reactions. (1 point)
iii. Add the equations and simplify to get a balanced equation. (1 point)

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

the objects have the same charge.