What is the pH of an aqueous solution with [H3O+] = 6×10−12 M ?

pH = 10.92

Explanation:

To determine the pH of an aqueous solution, we use the following mathematical relation; pH = - log [H3O+]

                                           = - log (6 x 10∧ -12)

                                           = 12 - 1.08

                                   pH =  10.92

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally