Which equation shows how to calculate how many grams (g) of koh would be needed to fully react with 4 mol mg(oh)2? the balanced reaction is: . mgcl2 + 2koh mg(oh)2 + 2kcl

The mass of KOH will be 448 grams.

Explanation:

For the given chemical reaction:

By Stoichiometry of the reaction:

1 mole of magnesium chloride reacts with 2 moles of potassium hydroxide.

So, 4 moles of magnesium chloride will react with = of potassium hydroxide.

To calculate the number of moles, we use the equation:

Moles of potassium hydroxide = 8 mol

Molar mass of potassium hydroxide = 56 g/mol

Putting values in above equation, we get:

Hence, the mass of KOH will be 448 grams.

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