A gas has a volume of 10 L at 0 C what is the final temperature of the gas if it volume increases to 25L

682.5K

Explanation:

Initial volume of gas V1 = 10L

Initial temperature T1 = 0°C

Convert temperature in Celsius to Kelvin

( 0°C + 273°C = 273K)

Final temperature T2 = ?

Final volume V2 = 25L

According to Charle's law, the volume of a fixed mass of a gas is directly proportional to the temperature.

Mathematically, Charles' Law is expressed as: V1/T1 = V2/T2

10L/273 = 25L/T2

To get the value of T2, cross multiply

10L x T2 = 273 x 25

10L x T2 = 6825 L

T2 = (6825L/10L)

T2 = 682.5K

Thus, the new temperature of the gas is 682.5K

the number of valence electrons for each molecule or ion is shown beneath the structure. remember hydrogen will not have more than two electrons. this hydrogen is part of a covalent bond (sharing two electrons). a double bond here would cause hydrogen to share four electrons with phosphorus.