How many molecules are in 3.55 miles of Aluminum Sulphate

2.14 x 10^24 molecules

Explanation:

Based on Avogadro's law:

1 mole of any substance has 6.02 x 10^23 atoms

So, 1 mole of ammonium sulphate = 6.02 x 10^23 molecules

3.55 moles of Aluminum Sulphate = Z molecules

To get the value of Z, cross multiply:

Z molecules x 1 mole = (6.02 x 10^23 molecules x 3.55 moles)

Z = 21.37 x 10^23 molecules

Z = 2.137 x 10^24 molecules (to 3 decimal place)

Rounded to nearest hundredth Z becomes 2.14 x 10^24

Thus, there are 2.14 x 10^24 molecules in 3.55 miles of Aluminum Sulphate.

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.