In this experiment, the student measured the change in temperature not for the system itself but for the surroundings (aqueous solution). The solution is very diluted and we can safely consider its specific heat and its density to be the same as for pure water: c=4.18 J/g-ºC and d=1.00 g/cm
In the SECOND experiment, the student mixed in a coffee cup calorimeter 58.0 mL of 0.25M H2SO4 solution and 42.0 mL of 0.60M NaOH solution.
Do you think that the change in temperature in the SECOND experiment was similar to the one recorded?
a. T2 b. T2 =T1: in the second experiment, the same amount of water was formed because hydroxide ion was a limiting reagent
c. T2=T1: in the second experiment, the same amount of water was formed because sulfuric acid was a limiting reagent
d. T2>T1: in the second experiment, more amount of water was formed because hydrochloric acid was the limiting reagent

The table lists pressure and volume values for a particular gas. which is the best estimate for the value of v at p = 7.0 × 103 pascals?

Reaction rate depends on how many molecules are coming into contact with each other with enough energy to react. increasing the temperature of the reactants will increase -

Nanotechnology, the field of trying to build ultrasmall structures one atom at a time, has progressed in recent years. one potential application of nanotechnology is the construction of artificial cells. the simplest cells would probably mimic red blood cells, the body's oxygen transporters. for example, nanocontainers, perhaps constructed of carbon, could be pumped full of oxygen and injected into a person's bloodstream. if the person needed additional oxygen-due to a heart attack perhaps, or for the purpose of space travel-these containers could slowly release oxygen into the blood, allowing tissues that would otherwise die to remain alive. suppose that the nanocontainers were cubic and had an edge length of 24 nanometers. part a part complete what is the volume of one nanocontainer? (ignore the thickness of the nanocontainer's wall.) express your answer using two significant figures. v v = 1.4ă—10â’20 l previous answers correct significant figures feedback: your answer 1.3824â‹…10â’20 = 1.382ă—10â’20 l was either rounded differently or used a different number of significant figures than required for this part. if you need this result for any later calculation in this item, keep all the digits and round as the final step before submitting your answer. part b suppose that each nanocontainer could contain pure oxygen pressurized to a density of 81 g/l . how many grams of oxygen could be contained by each nanocontainer?