If a certain mass of mercury has a volume of 0.002 m2 at a temperature of 20 celsius, what will be the volume of 50 celsius?

0.0022m3

Explanation:

Initial volume of mercury V1 = 0.002m3 (note that the unit of volume can be cm3, m3, dm3 or liters)

Initial temperature T1 = 20°C

Convert temperature in Celsius to Kelvin

( 20°C + 273°C = 293K)

Final temperature T2 = 50°C

( 50°C + 273°C = 323K)

Final volume V2 = ?

According to Charle's law, the volume of a fixed mass of a gas is directly proportional to the temperature.

Mathematically, Charles' Law is expressed as: V1/T1 = V2/T2

0.002/293 = V2/323

To get the value of V2, cross multiply

V2 = (323 x 0.002) / 293

V2 = 0.646 / 293

V2 = 0.0022 m3

Thus, the new volume of mercury will be 0.0022m3

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o