Four substances, HCl(g), I2(s), HI(g), and Cl2(g), are mixed in a reaction vessel and allowed to reach equilibrium in the reaction: 2HCl(g) + I2(s) ⇄ 2HI(g) + Cl2(g) Which of the following changes will result in an increased amount of HI(g) when equilibrium is reached again? X. Add HCl(g) to the reaction vessel. Y. Add I2(s) to the reaction vessel. Z. Increase the volume of the reaction vessel. A. X only B. X and Y only C. X and Z only D. Z only E. X, Y, and Z

B. X and Y only

Explanation:

Hello,

In this case, by considering the Le Chatelier's principle, if we desire an increase in the hydrogen iodide amount, based on the given reaction, two procedures are needed:

- Add HCl(g) to the reaction vessel: because the addition of a reagent shifts the reaction rightwards.

- Add I2(s) to the reaction vessel: by cause of the same aforesaid reason.

Therefore, the answer is: B. X and Y only.

Z statement is not true since the change in the mole number for the reaction is zero (2+1-2-1=0) considering each species' stoichiometric coefficients.

Best regards.

the formula would be mgso4

mgso[subscript]4

both adhesion and cohesion are attractions.

they are different in that adhesion is the force of attraction between the molecules of two different substances, whereas cohesion is the force of attraction between molecules of the same substance.

possible examples include capillary action, in which the adhesion between water and glass causes the water to rise in a narrow tube against the force of gravity.

because of hydrogen bonding, water is extremely cohesive.

this causes molecules on the surface of water to be drawn inward, which is why drops of water form beads on smooth surfaces.

hope this .