The explosive nitroglycerin (C3H5N3O9) decomposes rapidly upon ignition or sudden impact according to the following balanced equation:

4C3H5N3O9(l)→12CO2(g)+10H2O(g)+6N2( g)+O2(g) ΔH∘rxn=−5678kJ

Required:
Calculate the standard enthalpy of formation (ΔH∘f) for nitroglycerin.

Explanation:

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For the given reaction, the standard enthalpy of reaction is:

As long as the both nitrogen's and oxygen's standard enthalpies of formation are 0, thus, by looking for water's and carbon dioxide's standard enthalpies of formation, we compute the standard enthalpy of formation for nitroglycerin as shown below:

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explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.  

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