A solution is prepared using 0.125 g of glucose, , in enough water to make 250. G of total solution. The concentration of this solution, expressed in parts per million, is A) 5.00 x 101 ppm B) 5.00 x 102 ppm C) 5.00 x 103 ppm D) 5.00 x 104 ppm

Option B. 5×10² ppm

Explanation:

In order to determine the concentration of solution at ppm, we should know that ppm indicates mg of solute in 1kg of solution.

We convert the mass of solute from g to mg

0.125 g . 1000 mg / 1g = 125 mg

We convert the mass of solution from g to kg

250 g . 1 kg/ 1000 g = 0.250 kg

ppm = 125 mg / 0.250 kg = 500 ppm

answer

the ions in solute supperate from eachouthere

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is and electronic configuration of phosphorous is .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.  

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.