How many milliliters of 6.OM HCI are needed to prepare 150 mL of 0.65M HCI?
Dilution equation: M1 V1 = M2V2

V = 16.25 mL

Explanation: The dilution formula is expressed by the products of molarity and volume or M1V1 = M2V2. Derive the formula to find the initial volume.

V1 = M2V2 / M1

    = 0.65 M ( 150 mL ) / 6.0 M

    = 16.25 mL

Cancel out the units of molarity so that the remaining unit is in mL.

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

your answer is c) plasma

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