How many moles of O2 will be formed from 1.65 moles of KCIO3? (2KClO3–>2KCl + 3O2)

The number of mole of O₂ that will be formed from 1.65 moles of KClO₃ is 2.475 moles

The balanced equation is given below

From the balanced equation above,

2 moles of KClO₃ decomposed to produce 3 moles of O₂

From the balanced equation above,

2 moles of KClO₃ decomposed to produce 3 moles of O₂

Therefore,

1.65 moles of KClO₃ will decompose to produce = (1.65 × 3)/2 = 2.475 moles of O₂

Thus, 2.475 moles of O₂ were obtained from the reaction.

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2.475 mol of O2  formed.

Explanation:

Given 1.65 moles of KClO3 as the target amount in the reactant, used the coefficient of the balanced chemical reaction involved to determine the number of moles of O2 molecules formed.

x mole of  O2   = 1.65 mol  KClO3 x [(3 mol O2)/ (2 mol KClO3)] = 2.475 mol of O2

x mole of  O2 formed  = 2.475 mol of O2