What is the balanced equation for: Zinc reacts with Iron (III) Chloride yielding Zinc Chloride plus Iron Precipitate?

3Zn(s) + 2FeCl₃(aq) → 2Fe(s) + 3ZnCl₂ (aq)

Explanation:

This is a redox reaction where solid iron is formed by the reaction of Zn and Iron(III) chloride. We called redox because the iron is reduced and the zinc is oxidized.

The reactants are: Zn(s) and FeCl₃(aq)

The products are: ZnCl₂(aq) and Fe(s)

Zn(s) → Zn²⁺(aq) + 2e⁻      Oxidation

Fe³⁺(aq) + 3e⁻ → Fe(s)      Reduction

The e- are unballanced so we multiply the half reactions:

(Zn(s) → Zn²⁺(aq) + 2e⁻) . 3 →  3Zn(s) → 3Zn²⁺(aq) + 6e⁻

(Fe³⁺(aq) + 3e⁻ → Fe(s)) . 2 → 2Fe³⁺(aq) + 6e⁻ → 2Fe(s)

When we sum the half reactions, the electrons can be cancelled:

3Zn(s) + 2Fe³⁺(aq) + 6e⁻ → 2Fe(s) + 3Zn²⁺(aq) + 6e⁻

Balanced equation: 3Zn(s) + 2FeCl₃(aq) → 2Fe(s) + 3ZnCl₂ (aq)

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explanation:

58750.08068 is the answer i think