What is the pressure of 0.540 mol of an ideal gas at 35.5 L and 223 K?

0.715 kPa

2.45 kPa

28.2 kPa

62.7 kPa

28.2 kPa

Explanation:

This is a question for the Ideal Gases Law:

P . V = n . R . T → P = (n . R . T) / V

Let's replace data:

P = (0.540 mol . 0.082 L.atm/mol.K . 223 K) / 35.5 L

P = 0.278 atm

We convert the unit of pressure from atm to kPa

0.278 atm . 101.3 kPa / 1atm = 28.17 kPa ≅ 28.2 kPa

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