Answers: 3
⇄ 
=1/10;
![[C_3H_5O_3^{-} ]= c\alpha](/tpl/images/0563/3127/9e63c.png)
![[H^{+}] = c\alpha](/tpl/images/0563/3127/f7069.png)
can be neglected
![P_H =- log[H^{+} ]](/tpl/images/0563/3127/1ad61.png)
![c=\frac{1}{\alpha} \times [H^{+}]](/tpl/images/0563/3127/7fc04.png)
![[H^{+}] =antilog(-P_H)](/tpl/images/0563/3127/6a5c6.png)
![[H^{+} ] =0.0014](/tpl/images/0563/3127/a62ef.png)
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