Which insoluble compound in each pair should be more soluble in nitric acid than in pure water?

PbS or lead sulfide show less solubility in water and insoluble in nitric acid.

Explanation:

PbS dissociates in water.The reaction is -

PbS(s)⇄Pb²⁺ (aq) + S²⁻(aq)

The sulfide ion which is produced in the reaction is a strong comjugated base that contain weak acid like Hydrogen sulfide.The above reaction of S²⁻ with strong acid like nitric acid decrease the concentration of sulfide ion and results in equilibrium reacion  that shifts the equation to right side and thus increases the solubility.

S²⁻(Aq) + HNO₃(Aq)⇄ HS (Aq)+ NO₃ (Aq)

the best answer is d because the strong cohesion is caused by the ability of water molecules to undergo hydrogen bonding.

a is incorrect because when water solidifies, it becomes   ice, which expands and occupies a bigger volume for the same mass of water in its liquid state.

b is incorrect because water has high surface tension. besides bonding to itself it hydrogen bonds to other molecules at the top decreasing possibility for breaking of attractive forces.

c is incorrect because the water molecule has oxygen which is highly electronegative and so pulls the electron pair towards itself creating a dipole moment, making the molecule polar.

e is incorrect because water has strong adhesion, ability to stick to other molecules such as glass because of this molecules having stronger hydrogen bonding than water.