When 878 J of heat is added to 5 grams of oil at 34˚C , the temperature increases to 56˚C. Wha tis the specific heat of the oil?

The answer for the following problem is explained below.

The specific heat of oil is 7.98 J/gram °C

Explanation:

Given:

heat (q)=878 J

mass of oil (m) =5 grams

initial temperature () =34°C

final temperature () = 56°C

To solve:

specific heat of the oil (c)

We know;

c =q÷(mΔT)

ΔT= () - ()

ΔT =  56°C - 34°C

ΔT = 22°C

c =

c =878÷ 110

c =7.98 J/gram °C

Therefore the specific heat of oil is 7.98 J/gram °C

i belive it is water