If 155 J of heat energy is applied to a block of silver weighing 27.9 g, by how many degrees will the temperature of the silver increase?

The temperature of silver increase by 23.15 °C.

Explanation:

Given data:

Heat added = 155 j

Mass of silver = 27.9 g

How many degree temperature increase = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Specific heat capacity of silver is = 0.240 j/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Now we will put the values in formula.

155 j = 27.9 g × 0.240 j/g.°C  × ΔT

155 j = 6.696  j/°C  × ΔT

ΔT  = 155 j /6.696  j/°C

ΔT  = 23.15 °C

specific gravity is the density of a substance divided by the density of water. since (at standard temperature and pressure) water has a density of 1 gram/cm3, and since all of the units cancel, specific gravity is usually very close to the same value as density

so "c" is the answer

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number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.