What volume of carbon dioxide will 3.26 g of antacid made of calcium carbonate produce at 37.0 °C and 1.00 atm in the stomach according to the following reaction?
CaCO₃ (s) + 2 HCl (aq) → CaCl₂ (aq) + H₂O (l) + CO₂ (g)

0.830 mL of carbon dioxide will 3.26 g of antacid made of calcium carbonate produce at 37.0 °C and 1.00 atm.

Explanation:

Moles of calcium carbonate = 3.26 g

Moles of calcium carbonate =

According to reaction, 1 mol of calcium carbonate produces 1 mol of carbon dioxide gas, then 0.0326 moles of calcium carbonate will give :

of carbon dioxide.

Pressure of the gas = P = 1.00 atm

Temperature of the gas = T = 37.0°C = 37.0+ 273 K = 310 K

Volume of the gas = V

Moles of gas = n = 0.0326 mol

( ideal gas equation )

0.830 mL of carbon dioxide will 3.26 g of antacid made of calcium carbonate produce at 37.0 °C and 1.00 atm.

not clear