For the following reaction, 4.21 grams of hydrogen gas are allowed to react with 10.6 grams of ethylene (C2H4) . hydrogen(g) + ethylene (C2H4)(g) ethane (C2H6)(g) What is the maximum mass of ethane (C2H6) that can be formed? grams What is the FORMULA for the limiting reagent? C2H6 What mass of the excess reagent remains after the reaction is complete? grams

a)  11.34 g of ethane can be formed

b) is the limiting reagent

c) 3.44 g of the excess reagent remains after the reaction is complete

Explanation:

To calculate the moles :

1.

2.

According to stoichiometry :

1 mole of require 1 mole of

Thus 0.378 moles of will require=  of

Thus is the limiting reagent as it limits the formation of product and is the excess reagent.

moles of left = (2.10-0.378) = 1.72 moles

mass of left=

According to stoichiometry :

As 1 mole of give = 1 mole of

Thus 0.378 moles of give =  of

Mass of

Thus 11.34 g of ethane is formed.

d: the voltage of the secondary coil is less than that of the primary coil.

im not suree sorry if wrong