Two moles of aluminum chloride are dissolved in two liters of water.

How does the vapor pressure of the water change?

It does not change because the amount of water in the system remains constant in both systems, and water is the only volatile compound in this system.
It first decreases as aluminum chloride attracts the water molecules, but it then increases as dissolving completes and starts to push water molecules out.
It increases because aluminum and chloride ions displace water molecules, which escape into the gas phase.

It decreases because nonvolatile aluminum and chloride ions now occupy some of the volume of the system.

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

i have no clue hope you find the answer

it is the most commonly accepted one

it is the most commonly accepted one