6.0 L of gas in a piston at a pressure of 1.0 atm are compressed until the volume
is 3.5 LWhat is the new pressure inside the piston? *

1.71atm

Explanation:

The following were obtained from the question:

V1 (initial volume) = 6L

P1 (initial pressure) = 1atm

V2 (final volume) = 3.5L

P2 (final pressure) =?

Using the Boyle's law equation:

P1V1 = P2V2, the final pressure can be obtained as follow:

P1V1 = P2V2

1 x 6 = P2 x 3.5

Divide both side by 3.5

P2 = 6/3.5

P2 = 1.71atm

The final i.e the new pressure inside the piston is 1.71atm

just did the assignment and the answer was #1 +2 n

the answer is d. 74.02