How many grams of CaCl2 will be required in order to make a 60mL solution with the strength of 4M? M= mol solute / L of solution

26.6 g of CaCl₂ are required to make a 4M solution

Explanation:

4 M = Molarity of the solution

This is a type of concentratrion for solutions, that indicates the moles of solute in 1L of solution.

Solution's volume = 60 mL

We need to convert the volume from mL to L → 60 mL . 1L / 1000mL = 0.060L

Molarity = mol / volume (L) → Molarity . volume (L) = mol

4 M . 0.060L = 0.24 mol of solute

Let's convert the moles to mass → Molar mass CaCl₂

0.24 mol . 110.98 g / 1mol = 26.6 g

it's filtration, but this is an assumption so my apologies if i got this

your answer would be “dry”