How many grams of CsXeF7 can be produced from the reaction of 15.2 grams of CsF and 260 grams of XeF6?

39.72 g

Explanation:

Given data:

Mass of CsF = 15.2 g

Mass of XeF₆ = 260 g

Mass of Cs[XeF₇] = ?

Solution:

Chemical reaction:

CsF + XeF₆   →  Cs[XeF₇]

Number of moles of CsF:

Number of moles = mass/ molar mass

Number of moles = 15.2 g/151.9 g/mol

Number of moles = 0.1 mol

Number of moles of XeF₆ :

Number of moles = mass/ molar mass

Number of moles = 260 g/245.28 g/mol

Number of moles = 1.06 mol

Now we will compare the moles of Cs[XeF₇] with both reactants.

                            CsF               :            Cs[XeF₇]

                               1                 :                 1

                             0.1                :              0.1

                             XeF₆            :           Cs[XeF₇]

                                 1               :               1

                                1.06           ;              1.06

Number of moles of Cs[XeF₇] produce by  CsF are less so it will limiting reactant and limit the yield of Cs[XeF₇].

Mass of Cs[XeF₇]:

Mass = number of moles × molar mass

Mass = 0.1 mol × 397.2 g/mol

Mass = 39.72 g

explanation: it gains negative electrons, therefore becoming negatively charged. as charge cannot be created, nor destroyed, only transferred, this leaves the wool positive. now that they have opposite charges, the two items attract.

i'm assuming that the correct answer is indeed the first one/ "a"..