Consider an element Z that has two naturally occurring isotopes with the following percent abundances: the isotope with a mass number of 19.0 is 55.0% abundance and the isotope with a mass number of 21.0 is 45.0 % abundant. What is the atomic mass for element Z

The atomic mass for element Z is 19.9

Explanation:

Mass number and relative abundance of the first isotope is 19 and 55% respectively.

Mass number and relative abundance of the second isotope is 21 and 45% respectively.

Mass number of element Z = (0.55×19) + (0.45×21) = 10.45 + 9.45 = 19.90

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%

the answer is d.) potassium