You might need:
Calculator.
Periodic table
Given the following reaction:
Mg(OH), + 2HCI — MgCl2 + 2H2O
How many grams of MigCl, will be produced from 16.0 g of Mg
d 11.0 g of HCI?
grams (round to three significant figures)
Show Calculator
Show Periodic Table
HALL
Stuck? Watch a video or use a hint.
Report a pro

Mass = 14.3 g

Explanation:

Given data:

Mass of Mg(OH)₂  = 16.0 g

Mass of HCl = 11.0 g

Mass of MgCl₂ = ?

Solution:

Chemical equation:

Mg(OH)₂ + 2HCl    →   MgCl₂ + 2H₂O

Number of moles of Mg(OH)₂ :

Number of moles = mass/ molar mass

Number of moles = 16.0 g/ 58.3 g/mol

Number of moles = 0.274 mol

Number of moles of HCl :

Number of moles = mass/ molar mass

Number of moles = 11.0 g/ 36.5 g/mol

Number of moles = 0.301 mol

Now we will compare the moles of Mg(OH)₂  and HCl with MgCl₂.

                           Mg(OH)₂          :           MgCl₂

                                 1                 :               1

                                 0.274        :          0.274

                               HCl             :              MgCl₂

                                  2              :               1

                                0.301         :           1/2×0.301 = 0.150

The  number of moles of MgCl₂ produced by HCl are less so it will limiting reactant.

Mass of MgCl₂:

Mass = number of moles × molar mass

Mass = 0.150 ×  95 g/mol

Mass = 14.3 g

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.