A solution is made by mixing 24.G of acetyl bromide(CH3COBr) and 18.G of heptane (C7H16). Calculate the mole fraction of acetyl bromide in this solution

Mole fraction of acetyl bromide  → 0.52

Explanation:

To determine the mole fraction, we must need to convert the mass to moles.

Mole fraction = Moles of solute or solvent / Total moles

Moles of acetyl bromide = 24 g / 122.9 g/mol = 0.195 moles

Moles of heptane = 18 g /100 g/mol = 0.18 moles

Total moles = moles of heptane + moles of acetyl bromide

0.18 + 0.195 = 0.375 → Total moles

Mole fraction of acetyl bromide = 0.195 / 0.375 = 0.52

The mol fraction of acetyl bromide is 0.52

Explanation:

Step 1: Data given

Mass acetyl bromide = 24.0 grams

Molar mass of acetyl bromide = 122.95 g/mol

Mass of heptane = 18.0 grams

Molar mass of heptane =100.21 g/mol

Step 2: Calculate moles

Moles = mass / molar mass

Moles acetyl bromide = mass acetyl bromide / molar mass acetyl bromide

Moles acetyl bromide = 24.0 grams / 122.95 g/mol

Moles acetyl bromide = 0.195 moles

Moles heptane  = 18.0 grams / 100.21 g/mol

Moles heptane = 0.180 moles

Step 3: Calculate total moles

Total moles = 0.195 moles + 0.180 moles

Total moles = 0.375 moles

Step 4: Calculate mol fraction of acetyl bromide

Mol fraction acetyl bromide = moles acetyl bromide / total moles

Mol fraction acetyl bromide = 0.195 moles / 0.375 moles

Mol fraction acetyl bromide = 0.52

The mol fraction of acetyl bromide is 0.52

the child will have heterozygous dominant chromosomes as characters of his father are dominant over the characters of his mother.

the child is heterozygous