A galvanic cell is powered by the following redox reaction: Cl 2(g) + Mn 2 +(aq) + 2 H-On â 2 Cl-(aq) + MnO2(s) + 4 H + (aq) Answer the following questions about this cell. If you need any electrochemical data, be sure you get it from the ALEKS Data tab. Write a balanced equation for the half reaction that takes place at the cathode Write a balanced equation for the half- reaction that takes place at the anode. Calculate the cell voltage under standard conditions. Round your answer to 2 decimalEV places.

2.59V

Explanation:

Cathode half reaction equation:

Cl2(g) + 2e > 2Cl-(aq)

Anode half reaction equation:

Mn^2+(aq) + 2H2O(l) > MnO2(s) + 2e + 4H+

E°cathode= 1.36V

E°anode= -1.23V

E°cell= E°cathode - E°anode

E°cell= 1.36 - (-1.23)

E°cell= 2.59V

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer

explanation:

0.07 g/cm³

1.37 g/cm³