A concentration cell is constructed by placing identical iron electrodes in two Fe2 solutions. The potential of this cell is observed to be 0.047 V. If the more concentrated Fe2 solution is 0.10 M, what is the concentration of the other Fe2 solution

The concentration of other (diluted) solution is 0.0026 M

Explanation:

The half reactions for the cell is:

Oxidation half reaction (anode):  

Reduction half reaction (cathode):  

In this case, the cathode and anode both are same. So, will be equal to zero.

To calculate cell potential of the cell, we use the equation given by Nernst, which is:

where,

n = number of electrons in oxidation-reduction reaction = 2

= 0.047 V

= ? M

= 0.10 M

Putting values in above equation, we get:

Hence, the concentration of other (diluted) solution is 0.0026 M

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.