Calculate the molarity of a solution prepared by dissolving 224g of NaNO3 in 950 g of water. please show your work!

[NaNO₃] = 2.77 M

Explanation:

We  need the solution's density to determine molarity, but we assume that the volume of water is the total volume of solution.

As the mass of water is 950 g, with the water's density we can obtained the volume (δ H₂O = 1g/mL)  δ H₂O =  H₂O mass /  H₂O  volume

1g/mL = 950 g / H₂O volume → H₂O volume = 950 g / 1g/mL = 950 mL

We need the volume in L, so we convert it: 950 mL . 1L/1000 mL = 0.950L

Molarity (mol/L) are the moles of solute in 1L of solution → moles / vol (L)

We have the volume, so let's go for the moles of solute (mass/molar mass)

Mass of solute 224g NaNO₃ → 224 g / 85 g/mol = 2.63 moles

Molarity → 2.63 moles /0.950L = 2.77 M

c. is the answer

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