0.450 mol of aluminum hydroxide is allowed to react with 0.550 mol of sulfuric acid; the reaction which ensues is:
2Al(OH)3(s) + 3H2SO4(aq) >Al2(SO4)3(aq) + 6H2O(l)
How many moles of H2O can form under these conditions?
a. 0.183
b. 0.367 mol
c. 1.10 mol
d. 0.250 mol
e. 0.125 mol
Answers: 2
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0.450 mol of aluminum hydroxide is allowed to react with 0.550 mol of sulfuric acid; the reaction wh...
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