9.2 L of gas is inside of a large birthday balloon. How many male is that? (1L =1000mL)

For helium gas, it consists of 2300 moles and as the molecular weight of different gases will be changing the moles will be also be changing.

Explanation:

Generally, for determining the moles of any kind of objects, we find the ratio of amount of the object given to the molecular weight of the object.

As in the present case, 9.2 L of gas is said to be present inside the large balloon, then the weight of the gas present inside will be product of volume given with 1000 g. This is because, it is known that 1 L = 1000 g.

Mostly, balloons are filled with hydrogen, helium, Nitrous oxide, oxygen etc. Among them the vendors sell the balloons filled with helium gas.

So the moles of gas particles present in the balloon can be found by finding the ratio of weight of the gas particles to their molecular weight of the type of gas used.

Since, here the weight is fixed and we don't know the type of gas used, we are considering for helium. So the molecular weight of helium is 4 g.

Then,

So for helium gas, it consists of 2300 moles and as the molecular weight of different gases will be changing the moles will be also be changing.

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !

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