If trial 2 generated 37.49 mL of hydrogen gas at 22.00oC, use 714.4 pressure difference to determine what this volume corresponds to at STP.

V₂ = 24785.5 mL.

Explanation:

Given data:

Initial volume of hydrogen gas = 37.49 mL

Initial temperature = 22.0°C (22 + 273 = 295 K)

Initial pressure = 714.4 atm

Final temperature = 273 K

Final pressure = 1 atm

Final volume of hydrogen gas = ?

Solution;

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

V₂ = P₁V₁T₂  /T₁ P₂

V₂ = 714.4 atm × 37.49 mL × 273 K / 295 K × 1 atm

V₂ = 7311719.7 mL / 295

V₂ = 24785.5 mL.

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