What volume of chlorine gas at 38oC and 1.63 atm is needed to react completely with 10.4 grams of sodium to form sodium chloride according to the following balanced equation: 2Na (s) + Cl2 (g) 2NaCl (s).

5.5 litres is the volume of chlorine gas at 38oC and 1.63 atm is needed to react completely with 10.4 grams of sodium to form sodium chloride.

Explanation:

data given:

mass of sodium chloride in reaction = 10.4 grams

atomic mass of one mole of NaCl = 58.44 grams/mole

balanced equation for the reaction:

2Na (s) + Cl2 (g) 2NaCl (s).

number of moles =

                              =

                              = 0.17 moles of Na in the reaction.

from the reaction,

2 moles of Na  reacted with 1 mole of Cl2

0.17 moles of Na reacted with x moles

=

x = 0.35 moles of chlorine gas reacted to form NaCl

To know the volume following equation will be used:

PV = nRT

V =          R=0.0826 L atm/Mole.K, T = 311.15, P= 1.63 atm, n= 0.35 moles

V =

V = 5.5 litres is the volume of chlorine gas formed at given conditions.

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.