Give the percent yield when 162.8 g of CO2 are formed from the reaction of excess amount of C8H18 and with 218.0 grams of O2. (20 points)
2C8H18 + 25O2 → 16CO2 + 18H2O

Percent yield is 23.11 % when 162.8 g of CO2 are formed from the reaction of excess amount of C8H18 and with 218.0 grams of O2.

Explanation:

Balanced equation for the chemical reaction:

2C8H18 + 25O2 → 16CO2 + 18H2O

data given:

CO2 formed (actual yield)  = 162.8 grams

mass of oxygen = 218 grams

16 moles of CO2 formed when 5 moles of oxygen reacted

3.6 moles of CO2 formed when 6.8 moles of oxygen reacted.

In the reaction 16 moles of CO2 will have 44.01 x 16

                                      theoretical yield of CO2    = 704.16 grams

percent yield =   x100

         putting the values in the above equation

percent yield =  x 100

                       = 0.23 x 100

                           = 23.11 %

Percent yield is 23.11 %.

93.2 ml + 3920 ml = 4013 ml total  

(93.2 ml) * (2.03 m) / (4013 ml) = 0.0471 m

the volume in in l of the diluted solution would be 0.0471 m.

c, liquids evaporate, creating a gas