Plz anybody could answer it

2.88 x 10⁻¹³mol

Explanation:

Given parameters:

Concentration of chlorophyll in seawater = 1.2nanomoldm⁻³

Volume of seawater  = 1cm³

Unknown:

Mass of magnesium present = ?

Solution:

To solve this problem, we need to obtain the number of moles of the solute in the sea water.

Since we have been given the value of concentration, our work is easy to do;

           Number of moles  = concentration  x volume

Let us convert the given volume to dm³;

                1000cm³ = 1dm³

                    1cm³ is  = 0.001dm³

      Number of moles  = 1.2nanomoldm⁻³ x 0.001dm³

                                       = 1.2 x 10⁻³ nanomol

                                       = 1.2 x 10⁻³ x 10⁻⁹mol

                                      = 1.2 x 10⁻¹²mol

Formula of the compound:

             C₅₅ H₇₇ Mg N₄ O₅

        1 mole of C₅₅ H₇₇ Mg N₄ O₅ contains 1 mole of Mg

       1.2 x 10⁻¹²mol of C₅₅ H₇₇ Mg N₄ O₅ will contain  1.2 x 10⁻¹²mol of Mg

Since we now know the number of moles of Mg;

          Mass  = number of moles x molar mass

                      = 1.2 x 10⁻¹²  x 24

                      = 28.8 x 10⁻¹²mol

                       = 2.88 x 10⁻¹³mol

a rain shadow is a dry region of land on the side that is protected against the prevailing winds of a mountain range. the prevailing winds are the winds that occur most of the time in a particular place of the earth

prevailing winds carry air toward the mountain range. as the air rises up over a mountain range, the air cools, water vapor condenses, and clouds form. on this side of the mountains, called the windward side, precipitation falls in the form of  rain  or snow. this dry air produces a  rain shadow.

i think   the answer is c hope i'm right