Calculate ΔS for the isothermal compression of 3.05 mol of Cu(s) from 1.00 bar to 1370. bar at 298 K. α=0.492×10−4K−1,κT=0.78×10−6 bar−1, and the density is 8.92 g⋅cm−3.

Explanation:

For compression, equation for entropy change () is as follows.

              =  

Hence, for an isothermal process

Now, we will put the given values into the above formula as follows.

           =            = -0.146 J/K

Thus, we can conclude that value of for the isothermal compression is -0.146 J/K.

d: the voltage of the secondary coil is less than that of the primary coil.

im not suree sorry if wrong

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml