How many grams of nitrogen are needed to produce 100 grams of ammonia gas?

82.4 grams N₂(g)

Explanation:

3H₂(g) + N₂(g) => 2NH₃(g)

Assume excess H₂(g).

Convert gms NH₃ to moles, solve for moles of N₂ by rxn ratio then convert back to grams N₂(g).

Moles NH₃(g) = 100g/17g·mol⁻¹ = 5.882 mole NH₃(g)

Production of 5.882 mole NH₃(g) requires 1/2(5.882) mole N₂(g) = 2.9941 mole N₂(g)

Grams N₂(g) needed = 2.9941 mole N₂(g) x 28 gms/mole = 82.4 gms N₂(g).

for points guys