A solution is composed of 1.15 mL of diethyl ether (C4H10O, density=0.7134 g/mL) dissolved in 78.85 mL of dichloromethane (CH2Cl2, density=1.3266 g/mL). What is the molarity of the solution?

Molarityof the solution is 0.1375 M.

Explanation:

We will first find the number of moles of diethyl ether (C4H10O)  by finding its molar mass and measured mass.

Molar mass of diethyl ether (C4H10O) = 74.12 g.

Now, volume of diethyl ether (C4H10O) = 1.15 mL and its density = 0.7134 g/mL.

Therefore,  measured mass of diethyl ether (C4H10O) = volume x  density = 1.15 mL x 0.7134 g/mL = 0.82 g.

Now, number of moles of diethyl ether (C4H10O) =

= 0.011 Moles.

Volume of the solution = volume of diethyl ether + volume of dichloromethane = 1.15 mL + 78.85 mL = 80 mL.

Now, molarity of the solution = Number of moles of diethyl ether / Volume of the solution( in  mL) x 1000 =  

assuming that your periodic table has eighteen columns, you should highlight   the four elements in the third column from the left of the table.

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the have energy higher than those in the orbital while lower than those of the orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the orbital is therefore filled right after orbitals and before orbitals.  

potassium has electron configuration and calcium . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the and should be highlighted as well.

it can be observed without changing the identity of the object.

it depends on what substance you're talking about as well as many other factors. in quantum mechanics, the observation of particles affects the observers ability to measure certain properties. for example: you can know the velocity of a particle, but you can't know it's position; or you can know it's position, but not it's velocity. it's like trying to find out where a grain of sand is by throwing other grains of sand at it. once you find out where it is, it's been moved. it's also like trying to find an answer to the question of whether or not a tree falling in a forest makes a sound if nobody is there to hear it. paradoxically, the only way to find out is to be there and hear it.