Chemistry, 20.03.2020 17:56 annamerryberry1016

Aluminum metal reacts with aqueous iron(III) oxide to form aqueous aluminum oxide and iron metal. What is the stoichiometric coefficient for aluminum when the chemical equation is balanced using the lowest, whole-number stoichiometric coefficients

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The stoichiometric coefficient for aluminum when the chemical equation is balanced using the lowest, whole-number stoichiometric coefficients is 2

From the question,

We are to determine the stoichiometric coefficient for aluminum when the chemical equation for the reaction is balanced

The balanced chemical equation, using the lowest whole-number stoichiometric coefficient, for the reaction between aluminum metal and aqueous iron(III) oxide to form aqueous aluminum oxide and iron metal is

2Al(s) + Fe₂O₃(aq) → Al₂O₃(aq) + 2Fe(s)

Hence, the stoichiometric coefficient for aluminum when the chemical equation is balanced using the lowest, whole-number stoichiometric coefficients is 2

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Answer from: shimmerandshine1

The stoichiometric coefficient for aluminum is 2

Explanation:

Step 1: Data given

Aluminum metal = Al(s)

aqueous iron(III) oxide = Fe2O3(s)

aqueous aluminum oxide = Al2O3(s)

iron metal = Fe(s)

Step 2: The unbalanced equation

Al(s) + Fe2O3(s) → Al2O3(s) + Fe(s)

Step 3: Balancing the equation

On the left side we have 1x Al , on the right we have 2x Al (in Al2O3). To balance the amount of Al on both sides, we have to multiply Al (on the left side) by 2.

2Al(s) + Fe2O3(s) → Al2O3(s) + Fe(s)

On the left side we have 2x Fe (in Fe2O3) , on the right we have 1x Fe. To balance the amount of Fe on both sides, we have to multiply Fe (on the right side) by 2. Now the equation is balanced.

2Al(s) + Fe2O3(s) → Al2O3(s) +2Fe(s)

The stoichiometric coefficient for aluminum is 2

Answer from: Quest

The molecules contain like 54 of water

Answer from: Quest

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3

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