Chemistry, 20.03.2020 11:03 blakemccain1928
What is the ph of a solution with a [OH] of 3.31x10 -7 M
Answers: 3
![pOH=-\log[OH^-]](/tpl/images/0556/0127/fe336.png)
![[OH^-]=3.31\times 10^{-7}](/tpl/images/0556/0127/5f595.png)
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