Romine vapor in a 5.00-liter container at 300 K and 0.205 bar is to be heated to 340 K. Calculate the heat (kJ) that must be transferred to the gas to achieve the desired temperature increase, assuming that ˆ U Uˆ is independent of pressure.

The heat required to raise the temperature Q = 78.7 J

Explanation:

Given data

Volume = 5 liter = 0.005

Pressure = 0.205 bar = 20.5 k pa

Initial temperature = 300 K

Final temperature = 340 K

specific heat = 0.473

Gas constant R = 0.082

From  the ideal gas equation

= m R

Put all the values in above formula we get,

⇒ 20.5 × 0.005 = m × 0.082 × 300

⇒ m = 0.00416 kg

Heat required Q = m × C × ( )

⇒ Q = 0.00416 × 0.473 × ( 340 - 300 )

⇒ Q = 0.0787 KJ

⇒ Q = 78.7 J

This is the heat required to raise the temperature.

specific gravity is the density of a substance divided by the density of water. since (at standard temperature and pressure) water has a density of 1 gram/cm3, and since all of the units cancel, specific gravity is usually very close to the same value as density

so "c" is the answer

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