How many grams of lithium nitrate, LiNO3 (68.9 g/mol), are required to prepare 342.6 mL of a 0.783 M LiNO3 solution ? A) 0.00389 g B) 18.5 g C) 0.0541 g D) 30.1 g E) 0.00635 g

b) 18.5 g

Explanation:

The first step is the calculation of number of moles of with the molarity equation, so:

With the volume in "L" units (342.6 mL= 0.342 L ) we can find the moles, so:

Now, we have to calculate the molar mass to convert the moles to grams. For this we have to know the atomic mass of each atom:

Li ( 6.94 g/mol)

N (14 g/mol

O (16 g/mol)

With these values and the number of atoms in the molecule we can do the math:

(6.94 x 1) + ( 14 x 1) + (16 x 3 ) = 68.94 g/mol

The final step is the calculation of the grams, so:

We will need 18.5 g of LiNO3 to do a 0.783 M solution with a volume 342.6 mL.

hurricanes form when warm, moist air from the ocean surface quickly rises into the atmosphere and forms storm clouds and rain. when the clouds are formed, heat is released which warms the cool air in the upper regions of the atmosphere so that the cycle can continue. which two phases of the water cycle are repeated in this process?