2KCIO3 > 2KCI + 302
How many grams of O2 will be formed from 6.7 grams of KCIO3?

2.6253 g O2 formed  

Explanation:

Given 6.7 moles of KClO3 as the target amount in the reactant, used the coefficient of the balanced chemical reaction involved to determine the number of grams of O2 molecules formed.  

x g O2 = 6.7 g KClO3 x [(1 mol KClO3)/ (122.5 g KClO3)] x [(3 mol O2)/ (2 mol KClO3)] x [(32 g O2)/ (1 mol O2)]  

x g O2  = 2.6253 g O2 formed  

explanation: no but i do not usually comment

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :