If the reaction of phosphate ion with water is ignored, what is the total concentration of ions in a solution prepared by dissolving 7.00 g of K3PO4 in enough water to make 350. mL of solution?

0.377 M

Explanation:

Given that:

mass of = 7.00 g

the molar mass of  = 212.27 g/mol

number of moles =

number of moles of =

= 0.0330

The dissociation of K₃PO₄(aq) → 3K⁺(aq) + PO₄³⁻(aq)

So number of Ions formed = 3 K + and 1 PO₄³⁻ = 4 ions

No of moles of ions = 4 × 0.0330

Molarity = 4 × 0.0330/ ( 350/1000)  

= 0.377 M

Hence, the   total concentration of ions in a solution prepared by dissolving  7.00 g of K3PO4 in enough water to make 350. mL of solution = 0.377 M

h

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.