Chemistry, 20.03.2020 03:01 emily0259

Imagine 6.32 g each of Ar, Kr, and He are placed in a 10.3 L fixed container at 27 ∘C. Calculate the partial pressure of each species. Calculate the total pressure of each species.

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Answer from: hahHcjckk

Partial pressure Ar = 0.378 atm

Partial pressure Kr = 0.180 atm

Partial pressure He = 3.776 atm

Total pressure = 4.334 atm

Explanation:

Step 1: Data given

Mass of Ar = 6.32 grams

Molar mass of Ar = 39.95 g/mol

Mass of Kr = 6.32 grams

Molar mass Kr = 83.80 g/mol

Mass of He = 6.32 g/mol

Molar mass of He = 4.00 g/mol

Volume = 10.3 L

Temperature = 27.0 °C

Step 2: Calculate moles

Moles = mass / molar mass

Moles Ar = 6.32 grams / 39.95 g/mol

Moles Ar = 0.158 moles

Moles Kr = 6.32 grams / 83.80 g/mol

Moles Kr = 0.0754 moles

Moles He = 6.32 grams / 4.00 g/mol

Moles He = 1.58 moles

Step 3: Calculate partial pressures

p*V= n*R*T

p(Ar) = (n*R*T)/V

⇒p(Ar) = the partial pressure of Ar gas = TO BE DETERMINED

⇒n= the number of moles of Ar =0.158 moles

⇒R = the gas constant = 0.08206 L*atm/mol*K

⇒T = the temperature = 27 +273 = 300 K

⇒V = the volume = 10.3 L

p(Ar) = (0.158 * 0.08206 * 300) / 10.3

p(Ar) = 0.378 atm

p(Kr) = (n*R*T)/V

⇒p(Kr) = the partial pressure of Kr gas = TO BE DETERMINED

⇒n= the number of moles of Kr =0.0754 moles

⇒R = the gas constant = 0.08206 L*atm/mol*K

⇒T = the temperature = 27 +273 = 300 K

⇒V = the volume = 10.3 L

p(Kr) = (0.0754 * 0.08206 * 300) / 10.3

p(Kr) = 0.180 atm

p(He) = (n*R*T)/V

⇒p(He) = the partial pressure of He gas = TO BE DETERMINED

⇒n= the number of moles of He =1.58 moles

⇒R = the gas constant = 0.08206 L*atm/mol*K

⇒T = the temperature = 27 +273 = 300 K

⇒V = the volume = 10.3 L

p(He) = (1.58 * 0.08206 * 300) / 10.3

p(He) = 3.776 atm

Step 4: Calculate the total pressure

Total pressure = p(Ar) +p(Kr) +p(He)

Total pressure = 0.378 atm + 0.180 atm + 3.776 atm

Total pressure = 4.334 atm

Answer from: Quest

answer: the rate of diffusion increases with increase in temperature.

increase in temperature, increases the molecular/particles speed (kinetic energy. diffusion means movement of particles through the material.

generally, the heavier the particle the more it interacts with the environment and more the temperature matters. so higher temperature results in higher diffusion.

Answer from: Quest

D-no effect on the rate

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Imagine 6.32 g each of Ar, Kr, and He are placed in a 10.3 L fixed container at 27 ∘C. Calculate the...

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