A 0.228 mol sample of Ar gas is contained in a 6.00 L flask at room temperature and pressure. What is the density of the gas, in grams/liter, under these conditions?

Density of Ar gas under the given condition is 1.52 g/L

Explanation:

Density in grams/liter = (mass of Ar gas present in flask)/(volume of flask)

We know, number of moles = (mass)/(molar mass)

Molar mass of Ar = 39.948 g/mol

So, mass of 0.228 mol of Ar =

Volume of flask = 6.00 L

So, density of gas inside flask =

Hence, density of Ar gas under the given condition is 1.52 g/L

answer: c. the experiment shows that the red substance experienced a chemical change.

explanation: chemical change is the change in which chemical composition of the substance changes. physical change is the change in which there is no change in chemical composition.

chemical changes are accompanied by following changes:

a) precipitate formation

b) energy is released or absorbed

c) formation of bubbles

d) change in color

as it is given that the red color has disappeared and there is production of gas, it means the red substance has undergone a chemical change.

e

the answers would be

the first one and the second one